6th Class Mathematics Data Handling Question Bank Data Handling

  • question_answer
    Read the pictograph and find the value of \[\frac{\text{(P-Q+R)}}{\text{98}}\text{ }\!\!\times\!\!\text{ S}\]
    Name Number of Stuffed Toy Animals
    Jassi
    Jai
    Javed
    Joy
    1 =98 Stuffed Toy Animals
    (i) The number of stuffed toy animals Jassi and Joy both have is   P .
    (ii)  Javed has   Q   more stuffed toy animals than Jassi.
    (iii) The total number of stuffed toy animals owned by all the students is   R _.
    (iv) The number of stuffed toy animals Joy has less than Javed is   S   .

    A)  784

    B)  796

    C)  854

    D)  None of these

    Correct Answer: A

    Solution :

    · Number of stuffed toy animals Jassi has \[=2\times 98=196\] · Number of stuffed toy animals Jai has \[=5\times 98=490\] · Number of stuffed toy animals Javed has \[=3\times 98=294\] · Number of stuffed toy animals Joy has \[=2.5\times 98=245\] (i) Total number of stuffed toy animals Jassi and Joy both has = 196 + 245 = 441 (ii) Javed has 294 - 196 = 98 more stuffed toy animals than Jassi. (iii) Total number of stuffed toy animals owned by all the students = 196 + 490 + 294 + 245 = 1225 (iv) The number of stuffed toy animals Joy has less than Javed = 294 - 245 = 49 \[\therefore \] P = 441, Q = 98, R = 1225, S = 49 \[\Rightarrow \frac{\text{(P - Q + R)}}{\text{98}}\text{  }\!\!\times\!\!\text{  S = }\frac{\text{(441 - 98 + 1225)}}{\text{98}}\text{  }\!\!\times\!\!\text{  49}\] \[\text{=784}\]


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