In which month is there \[1\frac{1}{5}\] times as many visitors as In September
A) September
B) November
C) October
D) December
Correct Answer: B
Solution :
Number of visitors in September \[=240+360=600\] Now, \[\left( 1\frac{1}{5}\,\,\,of\,\,600 \right)\] \[=\frac{6}{5}\times 600\] \[=6\times 120=720\] Now, from graph we can see that, Number of visitors in October \[=\text{ }120+180=300\] Number of visitors in November \[=300+420=720\] Number of visitors in December \[=\text{ }400+500=900\] \[\therefore \]Required month is November.
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