A) 0
B) 1
C) \[\omega \]
D) \[i\]
Correct Answer: A
Solution :
\[\Delta \,=\left| \begin{matrix} 1 & 1+i+{{\omega }^{2}} & {{\omega }^{2}} \\ 1-i & -1 & {{\omega }^{2}}-1 \\ -i & -i+\omega -1 & -1 \\ \end{matrix} \right|\] \[=\left| \begin{matrix} 1 & i-\omega & {{\omega }^{2}} \\ 1-i & -1 & {{\omega }^{2}}-1 \\ -i & -i+\omega -1 & -1 \\ \end{matrix} \right|\]= 0 (\[\because \]Two rows are identical)
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