A) \[-1+i\sqrt{3}\]
B) \[-1-i\sqrt{3}\]
C) 2
D) All of these
Correct Answer: D
Solution :
\[{{(8)}^{1/3}}=x\Rightarrow {{x}^{3}}-8=0\] Þ \[(x-2)\,({{x}^{2}}+2x+4)=0\]. Þ \[x=2,\,2\omega ,\,2{{\omega }^{2}}\] or \[x=2,\,-1+i\sqrt{3},\,-1-i\sqrt{3}\].
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