A) \[-{{1.86}^{o}}C\]
B) \[-{{0.93}^{o}}C\]
C) \[-{{0.093}^{o}}C\]
D) \[{{0.93}^{o}}C\]
Correct Answer: C
Solution :
\[\Delta {{T}_{f}}={{K}_{f}}\times \text{molality}=\text{1}\text{.86}\times \text{0}\text{.05}=\text{0}\text{.093}\]°C Thus freezing point = 0 ? 0.093 = \[-{{0.093}^{o}}C\].
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