JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Depression of freezing point of the solvent

  • question_answer
    An aqueous solution of a non-electrolyte boils at \[{{100.52}^{o}}C\]. The freezing point of the solution will be

    A)                 \[{{0}^{o}}C\]   

    B)             \[-{{1.86}^{o}}C\]

    C)                 \[{{1.86}^{o}}C\]             

    D)                 None of the above

    Correct Answer: B

    Solution :

             \[\Delta {{T}_{b}}={{K}_{b}}\times m\] i.e. \[0.52=0.52\times m\]                 \[\Delta {{T}_{f}}={{K}_{f}}\times m=1.86\times 1=1.86\]; \[{{T}_{f}}=-{{1.86}^{o}}C\].


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