JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Depression of freezing point of the solvent

  • question_answer
    The freezing point of one molal \[NaCl\] solution assuming \[NaCl\]  to be 100% dissociated in water is (molal depression constant = 1.86) [CPMT 1985; BHU 1981; MP PMT 1997; UPSEAT 2001]

    A)                 \[-{{1.86}^{o}}C\]            

    B)                 \[-{{3.72}^{o}}C\]

    C)                 \[+{{1.86}^{o}}C\]

    D)                 \[+{{3.72}^{o}}C\]

    Correct Answer: B

    Solution :

             For \[NaCl\] \[i=2\]            \[\Delta {{T}_{f}}=2{{K}_{f}}m=2\times 1.86\times 1=3.72\]                 \[{{T}_{s}}=T-\Delta {{T}_{f}}=0-3.72=-3.72{}^\circ C\]


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