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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Depression of freezing point of the solvent

  • question_answer
    After adding a solute freezing point of solution decreases to ? 0.186. Calculate \[\Delta {{T}_{b}}\] if \[{{K}_{f}}=1.86\] and \[{{K}_{b}}=0.521\]. [Orissa JEE  2002, 04; MP PET/PMT 1998; AIEEE 2000]

    A)                 0.521     

    B)                 0.0521

    C)                 1.86       

    D)                 0.0186

    Correct Answer: B

    Solution :

               \[\Delta {{T}_{f}}={{K}_{f}}\times m\] Þ \[0.186=1.86\times m\]                    So \[m=0.1\],  Put the value of \[m\] in \[\Delta {{T}_{b}}={{K}_{b}}\times m\]                                 \[\Delta {{T}_{b}}=0.521\times (0.1)=0.0521\]


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