A) NaCl
B) Urea
C) Glucose
D) \[{{K}_{2}}S{{O}_{4}}\]
Correct Answer: D
Solution :
\[NaCl\to N{{a}^{+}}+C{{l}^{-}}=2\]ions \[{{K}_{2}}S{{O}_{4}}\to 2{{K}^{+}}+SO_{4}^{2-}=3\]ions \[{{K}_{2}}S{{O}_{4}}\]give maximum ion in solution so it shows maximum depression in freezing point.
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