A) \[{{0.85}^{o}}C\]
B) \[-{{3.53}^{o}}C\]
C) \[{{0}^{o}}C\]
D) \[-{{0.35}^{o}}C\]
Correct Answer: B
Solution :
\[\underset{(1-\alpha )}{\mathop{HBr}}\,\] ⇌ \[\underset{\alpha }{\mathop{{{H}^{+}}}}\,+\underset{\alpha }{\mathop{B{{r}^{-}}}}\,\] Total = 1 + a \ \[i=1+\alpha =1+0.9=1.9\] \[\Delta {{T}_{f}}=i\,{{K}_{f}}\times m=1.9\times 1.86\times \frac{8.1}{81}\times \frac{1000}{100}={{3.53}^{o}}C\] \[{{T}_{f}}=-{{3.53}^{o}}C\].
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