A) \[{{e}^{-a{{x}^{2}}}}(\cot x+2ax\log \sin x)\]
B) \[{{e}^{-a{{x}^{2}}}}(\cot x+ax\log \sin x)\]
C) \[{{e}^{-a{{x}^{2}}}}(\cot x-2ax\log \sin x)\]
D) None of these
Correct Answer: C
Solution :
\[\frac{d}{dx}\{{{e}^{-a{{x}^{2}}}}\log (\sin x)\}\] \[={{e}^{-a{{x}^{2}}}}(-2ax).\log (\sin x)+{{e}^{-a{{x}^{2}}}}\cot x\] \[={{e}^{-ax}}^{2}[\cot x-2ax\log (\sin x)]\].You need to login to perform this action.
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