A) 120 volts
B) 160 volts
C) 220 volts
D) 240 volts
Correct Answer: D
Solution :
\[{{R}_{1}}=80\times 200=16000\,\Omega =16\,k\Omega \] Current flowing through \[{{V}_{1}}\]= Current flowing through \[{{V}_{2}}\] = \[\frac{80}{16\times {{10}^{3}}}=5\times {{10}^{-3}}A\]. So, potential differences across \[{{V}_{2}}\] is \[{{V}_{2}}=5\times {{10}^{-3}}\times 32\times {{10}^{3}}=160\,\text{volt}\] Hence, line voltage \[V={{V}_{1}}+{{V}_{2}}=80+160=240V\].You need to login to perform this action.
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