A) 0.8 V
B) 1.6 V
C) 0.08 V
D) 0.16 V
Correct Answer: D
Solution :
\[E=\frac{e}{(R+{{R}_{h}}+r)}\,\frac{R}{L}\times l\]\[=\frac{2}{(10+40+0)}\times \frac{10}{1}\times 0.4=0.16V\].You need to login to perform this action.
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