A) \[36\times {{10}^{-8}}m.\]
B) \[6\times {{10}^{-8}}m.\]
C) \[\sqrt{6}\times {{10}^{-8}}m.\]
D) \[6\times {{10}^{-4}}m.\]
Correct Answer: D
Solution :
By using \[{{f}_{p}}=\frac{{{r}^{2}}}{(2p-1)\lambda }\] For first \[HPZ\] \[r=\sqrt{{{f}_{p}}\lambda }\,=\sqrt{0.6\times 6000\times {{10}^{-10}}}\] \[=6\times {{10}^{-4}}m.\]
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