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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Diffraction of Light

  • question_answer
    Light of wavelength \[589.3\,nm\] is incident normally on the slit of width \[0.1\,mm.\] What will be the angular width of the central diffraction maximum at a distance of \[1\,m\] from the slit                                                   [BHU (Med.) 1999]

    A)            \[0.68{}^\circ \]                   

    B)            \[1.02{}^\circ \]

    C)            \[0.34{}^\circ \]                   

    D)            None of these

    Correct Answer: A

    Solution :

               Angular width of central maxima \[=\frac{2\lambda }{d}\]\[=\frac{2\times 589.3\times {{10}^{-9}}}{0.1\times {{10}^{-3}}}\,rad\]                                         \[=0.0117\times \frac{180}{\pi }=0.68{}^\circ \]


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