A) \[{{0.36}^{o}}\]
B) \[{{0.18}^{o}}\]
C) \[{{0.72}^{o}}\]
D) \[{{0.09}^{o}}\]
Correct Answer: A
Solution :
The angular half width of the central maxima is given by \[\sin \theta =\frac{\lambda }{a}\]\[\Rightarrow \theta =\frac{6328\times {{10}^{-10}}}{0.2\times {{10}^{-3}}}\]rad \[=\frac{6328\times {{10}^{-10}}\times 80}{0.2\times {{10}^{-3}}\times \pi }\]degree = 0.18o Total width of central maxima \[=2\theta ={{0.36}^{o}}\]
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