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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Diffraction of Light

  • question_answer
    Direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by (a is the width of the slit)                                                       [KCET 1999]

    A)            \[a\sin \theta =\frac{\lambda }{2}\]                              

    B)            \[a\cos \theta =\frac{3\lambda }{2}\]

    C)            \[a\sin \theta =\lambda \]     

    D)            \[a\sin \theta =\frac{3\lambda }{2}\]

    Correct Answer: D

    Solution :

                       For nth secondary maxima path difference \[d\sin \theta =(2n+1)\frac{\lambda }{2}\] \[\Rightarrow \]\[a\sin \theta =\frac{3\lambda }{2}\]


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