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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Diffraction of Light

  • question_answer
    Light of wavelength\[\lambda =5000\,\,{AA}\]falls normally on a narrow slit. A screen placed at a distance of 1 m from the slit and perpendicular to the direction of light. The first minima of the diffraction pattern is situated at 5 mm from the centre of central maximum. The width of the slit is

    A) 0.1 mm                                   

    B) 1.0 mm

    C) 0.5 mm                                   

    D) 0.2 mm

    Correct Answer: A

    Solution :

    Position of nth minima \[{{x}_{n}}=\frac{n\lambda D}{d}\] \[\Rightarrow \] \[5\times {{10}^{-3}}=\frac{1\times 5000\times {{10}^{-10}}\times 1}{d}\] \[\Rightarrow \] \[d={{10}^{-4}}\,\,m=0.1\,\,mm\].


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