JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Diffraction of Light

  • question_answer
    The width of the nth HPZ will be

    A)            \[\sqrt{nb\lambda }\]      

    B)            \[\sqrt{b\lambda }\,[\sqrt{n}-\sqrt{n-1}]\]

    C)            \[(\sqrt{n}\,-\,\sqrt{n-1})\]   

    D)            \[\frac{\sqrt{b\lambda }}{[\sqrt{n}\,-\sqrt{n-1}]}\]

    Correct Answer: B

    Solution :

                       Width of nth HPZ   \[{{B}_{n}}={{r}_{n}}-{{r}_{n-1}}\] \[{{r}_{n}}=\sqrt{nb\lambda }\],  \[{{r}_{n-1}}=\sqrt{(n-1)b\lambda }\] \[{{B}_{n}}=\sqrt{nb\lambda }-\sqrt{(n-1)b\lambda }=\sqrt{b\lambda }\,[\sqrt{n}-\sqrt{(n-1)}]\]


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