A) 70 mm
B) 0.14 mm
C) 1.4 mm
D) 0.14 cm
Correct Answer: C
Solution :
Width of central maxima \[=\frac{2\lambda D}{d}\] \[=\frac{2\times 2.1\times 5\times {{10}^{-7}}}{0.15\times {{10}^{-2}}}=1.4\times {{10}^{-3}}m=1.4\ mm\]
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