A) Distance between slit and source
B) Wavelength of light used
C) Width of the slit
D) Frequency of light used
Correct Answer: A
Solution :
For single slit diffraction pattern \[d\sin \theta =\lambda \] (\[d=\]slit width) Angular width = \[2\theta =2{{\sin }^{-1}}\left( \frac{\lambda }{d} \right)\] It is independent of D i.e. distance between screen and slit
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