A) Methyl
B) Primary
C) Secondary
D) Tertiary
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} \,\,\,\text{Methyl} \\ \,\text{carbanion} \end{smallmatrix}}{\mathop{CH{{_{3}^{{}}}^{-}}\,\,}}\,>\,\underset{\begin{matrix} {} \\ \begin{matrix} {} \\ {{1}^{o}} \\ \end{matrix} \\ \end{matrix}}{\mathop{R-CH{{_{2}^{{}}}^{-}}\,>}}\,\underset{\,\,\,\,\,\,\,2{}^\circ }{\mathop{R-\underset{R\,\,\,}{\mathop{\underset{|\,\,\,\,}{\mathop{C{{H}^{-}}}}\,}}\,}}\,>\,\underset{\,\,\,\,\,\,\,\,3{}^\circ \,}{\mathop{R-\,\underset{R\,\,}{\overset{R\,\,}{\mathop{\underset{|\,\,\,\,}{\overset{|\,\,\,\,}{\mathop{{{C}^{-}}}}}\,}}}\,}}\,\]
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