A) Two free radicals
B) Two carbonium ions
C) Two carbanions
D) One cation and one anion
Correct Answer: D
Solution :
\[C-Cl\underset{\text{bond fission }}{\mathop{\xrightarrow{\text{Heterolytic }}}}\,\underset{\text{Cation}}{\mathop{{{C}^{+}}}}\,+\underset{\text{Anion}}{\mathop{C{{l}^{-}}}}\,\]
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