| Column - I | Column - II |
| P. \[x\] and \[y\] are in direct proportion and \[x=40\] when \[y=120\]. If \[x=60\] then \[y=\] | (i) 160 |
| Q. \[x\] varies inversely as \[y\] and \[x=12\] when \[y=300\], if \[x=24\] then \[y=\] | (ii) 180 |
| R. \[x\] varies directly as \[y\] and \[y=50\] when \[x=30\], if \[x=96\] then \[y=\] | (iii) 130 |
| S. \[x\] varies inversely as \[y\] and \[y=650\] when \[x=20\], if \[x=100\] then \[y=\] | (iv) 150 |
A) P\[\to \](iv); Q\[\to \](i); R\[\to \](iii); S\[\to \](ii)
B)
P\[\to \](ii); Q\[\to \](iv); R
(i); S(iii)
C) P\[\to \](iv); Q\[\to \](i); R\[\to \](iii); S\[\to \](ii)
D) P\[\to \](ii); Q\[\to \](iv); R\[\to \](i); S\[\to \](iii)
Correct Answer: D
Solution :
P. According to question, \[\frac{40}{120}=\frac{60}{y}\] Or \[y=\frac{60\times 120}{40}=180\] Q. According to question, \[12\times 300=24\times y\] or \[y=\frac{12\times 300}{24}=150\]. R. According to question, \[\frac{30}{50}=\frac{96}{y}\] Or \[y=\frac{96\times 50}{30}=160\] S. According to question, \[20\times 650=100\times y\] Or \[y=\frac{20\times 650}{100}=130\]
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