A) 120 hours
B) 80 hours
C) 40 hours
D) 60 hours
Correct Answer: D
Solution :
(d): Filling in 1 hr \[=\frac{1}{15}\]tank Let emptying by leak in 1 hr = \[\frac{1}{x}\]tank (where leak empties tank in 'x' hrs) \[\therefore \]Hrs in which it fills along with leak also emptying \[\Rightarrow \frac{1}{\frac{1}{15}-\frac{1}{x}}\] = 20hrs \[\Rightarrow \frac{1}{15}-\frac{1}{x}=\frac{1}{20}\] \[\Rightarrow \frac{1}{x}=\frac{1}{15}-\frac{1}{20}=\frac{5}{30}=\frac{1}{60}\] x = 60 hrs.You need to login to perform this action.
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