A) 80 metres
B) 100 metres
C) 140 metres
D) 260 metres
Correct Answer: B
Solution :
The movements of the child from A to E are as shown in fig Clearly, the child meets his father at E. Now AF = (AB - FB) = (AB - DC) = (90 - 30) m = 60m. EF = (DE - DF) = (DE - BC) = (100 - 20) m = 80m. \[\therefore \] Required distance \[=AE=\sqrt{A{{F}^{2}}+E{{F}^{2}}}\,=\sqrt{{{(60)}^{2}}+{{(80)}^{2}}}\] \[=\sqrt{3600+6400}\,=\sqrt{10000}=100\,m\].You need to login to perform this action.
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