question_answer

Rasik walks 20m North. Then, he turns right and walks 30m. Then he turns right and walks 35m. Then he turns left and walks 15m. Then he again turns left and walks 15 m. In which direction and how many meters away is he from his original position?                                      

A) 15 meters West   

B) 30 meters East            

C) 30 meters West   

D) 45 meters East

Correct Answer: D

Solution :

    The movements of Rasik from A to F are as shown in figure. Since\[CD\text{ }=\text{ }AB\text{ }+\text{ }EF\], so F lies in line with A. Rasik's distance from original position A = AF \[=\left( AG+GF \right)=\left( BC+DE \right)=\left( 30+15 \right)m=45m.\]Also, F lies to the east of A.