question_answer

X and Y start moving towards each other from two places 200 m apart. After walking 60 m, Y turns left and goes 20m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If X and Y walk with the same speed, what is the distance between them now?

A) 20 m                

B)   30 m

C) 40 m 

D)   50 m

E) None of these

Correct Answer: C

Solution :

Explanation Option [c] is correct. Clearly Y moves 60 m from Q. upto A, then 20 m upto B, 40 m upto C and then upto D. So, \[\operatorname{AD} = BC = 40 m\] Thus, \[\operatorname{Q}.D = AD + AQ = \left( 60 + 40 \right) m = 100 m\] Since X and Y travel with the same speed/ X will travel with the same speed along the horizontal as Y travels in the same time. Now, total distance travelled by \[\operatorname{Y} = \left( 60 + 20 + 40 + 20 \right) = 140 m\] So, X also travels 140 m upto A. Distance between X and \[\operatorname{Y} = AD = Q.D - AQ, = \left( 100 - 60 \right) m = 40 m.\]