A) \[3\times {{10}^{5}}m/s\]moving towards the earth
B) \[3\times {{10}^{5}}m/s\]moving away from the earth
C) \[3\times {{10}^{6}}m/s\]moving towards the earth
D) \[3\times {{10}^{6}}m/s\]moving away from the earth
Correct Answer: D
Solution :
\[\Delta \lambda =\frac{{{v}_{s}}}{c}\lambda \Rightarrow {{v}_{s}}=\frac{\Delta \lambda .c}{\lambda }=\frac{47\times 3\times {{10}^{8}}}{4700}\] \[=3\times {{10}^{6}}m/s\]away from earth
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