A) Moving away with velocity 1.2 ´ 106 m/s
B) Coming closer with velocity 1.2 ´ 106 m/s
C) Moving away with velocity 4 ´ 106 m/s
D) Coming closer with velocity 4 ´ 106 m/s
Correct Answer: A
Solution :
Using \[\frac{\Delta \lambda }{\lambda }=\frac{v}{c}\Rightarrow v=\frac{\Delta \lambda }{\lambda }c\] \[\Rightarrow v=0.004\times 3\times {{10}^{8}}=1.2\times {{10}^{6}}\]m/sec
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