A) \[\frac{2}{3}v\]
B) v
C) \[\frac{3}{2}v\]
D) 3v
Correct Answer: A
Solution :
\[{n}'=n\,\left( \frac{v}{v-{{v}_{S}}} \right)\]Þ\[\frac{n'}{n}=\frac{v}{v-{{v}_{S}}}\Rightarrow \frac{v}{v-{{v}_{S}}}=3\Rightarrow {{v}_{s}}=\frac{2v}{3}\]
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