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JEE Main & Advanced Physics Wave Mechanics Question Bank Doppler's Effect

  • question_answer
    A whistle giving out 450 Hz approaches a stationary observer at a speed of 33 m/s. The frequency heard by the observer in Hz is                                                        [IIT 1997 Cancelled]

    A)            409

    B)            429

    C)            517

    D)            500

    Correct Answer: D

    Solution :

               The apparent frequency heard by the observer is given by                    \[n'=\frac{v}{v-{{v}_{S}}}n\]= \[\frac{330}{330-33}\times 450=\frac{330}{297}\times 450=500\]\[Hz\]


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