A) \[\frac{1}{10}v\]
B) \[\frac{1}{2}v\]
C) \[\frac{1}{5}v\]
D) v
Correct Answer: A
Solution :
\[{{n}_{Before}}=\frac{v}{v-{{v}_{c}}}n\] and \[{{n}_{After}}=\frac{v}{v+{{v}_{c}}}.n\] \[\frac{{{n}_{Before}}}{{{n}_{After}}}=\frac{11}{9}=\left( \frac{v+{{v}_{c}}}{v-{{v}_{c}}} \right)\] Þ \[{{v}_{c}}\Rightarrow \frac{v}{10}\]You need to login to perform this action.
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