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JEE Main & Advanced Physics Wave Mechanics Question Bank Doppler's Effect

  • question_answer
    A source of sound of frequency 90 vibrations/ sec is approaching a stationary observer with a speed equal to 1/10 the speed of sound. What will be the frequency heard by the observer                                         [MP PMT 2000]

    A)            80 vibrations/sec                

    B)            90 vibrations/sec

    C)            100 vibrations/sec              

    D)            120 vibrations/sec

    Correct Answer: C

    Solution :

               \[n'=n\,\left( \frac{v}{v-{{v}_{s}}} \right)=90\,\left( \frac{v}{v-\frac{v}{10}} \right)\] = \[100\frac{Vibration}{\sec }\]


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