A) v
B) 2v
C) \[\frac{v}{2}\]
D) \[\frac{v}{4}\]
Correct Answer: C
Solution :
By using \[n'=\left( \frac{v}{v-{{v}_{S}}} \right)\Rightarrow 2n=n\,\left( \frac{v}{v-{{v}_{S}}} \right)\Rightarrow {{v}_{S}}\,=\frac{v}{2}\]
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