A) \[1\times {{10}^{-3}}N{{m}^{-1}}\]
B) \[10\times {{10}^{-3}}N{{m}^{-1}}\]
C) \[10\times {{10}^{-3}}Nm\]
D) \[1\times {{10}^{2}}N{{m}^{2}}\]
Correct Answer: C
Solution :
\[{{\tau }_{\max }}=pE=q\,(2l)E\] \[=2\times {{10}^{-6}}\times 0.01\times 5\times {{10}^{5}}\] \[=10\times {{10}^{-3}}N\text{-}m\]You need to login to perform this action.
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