A) 5 kV
B) 50 kV
C) 5 V
D) 50 V
Correct Answer: B
Solution :
By using \[\frac{1}{2}m{{v}^{2}}=QV\] Þ \[\frac{1}{2}\times 2\times {{10}^{-6}}\times {{(10)}^{2}}=2\times {{10}^{-6}}V\] Þ \[V=50\,kV\]You need to login to perform this action.
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