A) \[2.304\times {{10}^{-10}}N/C\]
B) \[14.4\,V/m\]
C) \[16\,V/m\]
D) \[1.44\times {{10}^{11}}N/C\]
Correct Answer: D
Solution :
\[E=\frac{q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\]\[=9\times {{10}^{9}}\times \frac{1.6\times {{10}^{-19}}}{{{({{10}^{-10}})}^{2}}}=1.44\,\times {{10}^{11}}N/C\]You need to login to perform this action.
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