A) Boric acid
B) Acetic acid
C) Sulphuric acid
D) Phosphoric acid
Correct Answer: C
Solution :
\[{{H}_{2}}S{{O}_{4}}\]⇌ \[{{H}^{+}}+{{H}^{-}}S{{O}_{4}}\]⇌\[{{H}^{+}}+SO_{4}^{-\,-}\] Because of it is completely ionised.You need to login to perform this action.
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