Banking Physics Electricity and Circuits Question Bank Electricity

  • question_answer
    In an A.C. circuit with voltage V and current I the power dissipated is

    A)  \[\frac{1}{\sqrt{2}}VI\]             

    B)  \[\frac{1}{2}VI\]

    C)  VI

    D)  dependent on the phase between V and I  

    Correct Answer: D

    Solution :

     Power dissipated \[={{E}_{rms}}.{{I}_{rms}}=({{E}_{rms}})({{I}_{rms}})\cos \theta \] Hence, power dissipated depends upon phase difference.


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