A) \[0.25\times {{10}^{-5}}{{m}^{2}}\]
B) \[0.50\times {{10}^{-3}}{{m}^{2}}\]
C) \[0.75\times {{10}^{-7}}{{m}^{2}}\]
D) \[1.00\times {{10}^{-4}}{{m}^{2}}\]
Correct Answer: C
Solution :
\[I=\text{625mm}=0.\text{625}\,\text{m};\text{R}=\text{4W}\] \[\rho =4.8\times {{10}^{-7}}ohm\,metre;A=?\] \[R=\rho \frac{l}{A}\Rightarrow A=\rho \frac{l}{R}\] \[A=\frac{4.8\times {{10}^{-7}}\times 0.625}{4}=0.75\times {{10}^{-7}}\] Area of cross section is\[~0.\text{75}\times \text{1}{{0}^{-\text{7}}}\text{ }{{\text{m}}^{\text{2}}}\]
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