A) 484 W
B) 400 W
C) 441 W
D) 369 W
Correct Answer: B
Solution :
V=200V; r= \[10\Omega \] R'= 10+ \[100\Omega \] = \[110\Omega \] \[I=\frac{V}{R'}=\frac{220}{100}=2A\] \[P={{I}^{2}}R=4\times 100=400W\]You need to login to perform this action.
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