A) 2 :1
B) 4 : 1
C) 1:2
D) 1 : 4
Correct Answer: B
Solution :
In series I is same, so\[V\propto R\propto \frac{1}{{{r}^{2}}}\] So, \[\frac{{{V}_{thin}}}{{{V}_{thick}}}={{\left( \frac{{{r}_{thick}}}{{{r}_{thin}}} \right)}^{2}}={{\left( \frac{2}{1} \right)}^{2}}=4:1\]You need to login to perform this action.
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