A) 5 : 8
B) 10 : 54
C) 18 : 5
D) 54 : 10
Correct Answer: A
Solution :
\[R=\rho \frac{L}{A},{{R}_{A}}:{{R}_{B}}\] \[(4\times 5)\div {{(2)}^{2}}:(9\times 18)\div {{(3)}^{2}}=\frac{20}{4}=5;\] \[\frac{72}{9}=8\] Hence, the resistance of wire A to the resistance of wire B = 5 : 8You need to login to perform this action.
You will be redirected in
3 sec