A) 250W
B) 500W
C) 1000W
D) 2000W
Correct Answer: D
Solution :
Resistance of each heater\[=\frac{{{V}^{2}}}{W}\] \[=\frac{250\times 250}{1000}=\frac{250}{4}\Omega \] Equivalent resistance of the combination of heater (connected in parallel). \[R'=\frac{{{R}_{1}}{{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}\] \[=\frac{250\times 250}{4\times 4\left( \frac{250}{4}+\frac{250}{4} \right)}=\frac{250}{8}\Omega \] \[\therefore \]Rate of heating\[=\frac{{{V}^{2}}}{R}=\frac{250\times 250\times 8}{250}\] \[=\mathbf{2000}\]watt
You need to login to perform this action.
You will be redirected in
3 sec
