A) \[{{x}^{2}}+{{y}^{2}}=9\]
B) \[{{x}^{2}}+{{y}^{2}}=4\]
C) \[{{x}^{2}}+{{y}^{2}}=13\]
D) \[{{x}^{2}}+{{y}^{2}}=5\]
Correct Answer: C
Solution :
The locus of point of intersection of two perpendicular tangents drawn on the ellipse is \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}+{{b}^{2}},\] which is called ?director- circle?. Given ellipse is \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{4}=1\], \Locus is \[{{x}^{2}}+{{y}^{2}}=13.\]You need to login to perform this action.
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