A) \[{{E}_{x}},\,{{B}_{y}}\]
B) \[{{E}_{y}},\,{{B}_{x}}\]
C) \[{{E}_{z}},\,{{B}_{x}}\]
D) \[{{E}_{y}},\,{{B}_{z}}\]
Correct Answer: A
Solution :
\[{{E}_{x}}\] and \[{{B}_{y}}\] would generate a plane EM wave travelling in z-direction. \[\vec{E}\], \[\vec{B}\] and \[\vec{k}\] form a right handed system \[\vec{k}\] is along z-axis. As \[\hat{i}\times \hat{j}=\hat{k}\] Þ \[{{E}_{x}}\hat{i}\times {{B}_{y}}\hat{j}=C\hat{k}\] i.e. E is along x-axis and B is along y-axis.
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