A) \[13.6\times {{10}^{6}}\,m/s\]
B) \[1.8\times {{10}^{2}}\,m/s\]
C) \[3.6\times {{10}^{8}}\,m/s\]
D) \[1.8\times {{10}^{8}}\,m/s\]
Correct Answer: D
Solution :
\[v=\frac{c}{\sqrt{{{\mu }_{r}}{{\varepsilon }_{r}}}}=\frac{3\times {{10}^{8}}}{\sqrt{1.3\times 2.14}}=1.8\times {{10}^{8}}m/sec\]
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