A) - 16
B) 16
C) 4
D) - 4
Correct Answer: B
Solution :
Given equation is \[a{{x}^{2}}-{{y}^{2}}+4x-y=0\] Here \[A=a,B=-1,\,H=0,\,G=2,F=\frac{-1}{2},\,C=0\] If the given equation represents a pair of straight lines, then \[ABC+2FGH-A{{F}^{2}}-B{{G}^{2}}-C{{H}^{2}}=0\] \[0-0-a\,\left( \frac{1}{4} \right)-(-1)(4)=0\] Þ \[\frac{-a}{4}=4=0\Rightarrow a=16\].You need to login to perform this action.
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