JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
    Circles are drawn through the point (2, 0) to cut intercept of length 5 units on the x-axis. If their centres lie in the first quadrant, then their equation is

    A)            \[{{x}^{2}}+{{y}^{2}}+9x+2fy+14=0\]

    B)            \[3{{x}^{2}}+3{{y}^{2}}+27x-2fy+42=0\]

    C)            \[{{x}^{2}}+{{y}^{2}}-9x+2fy+14=0\]

    D)            \[{{x}^{2}}+{{y}^{2}}-2fy-9y+14=0\]

    Correct Answer: C

    Solution :

               The circle g, f, c passes through (2, 0)                    \[\therefore \]\[4+4g+c=0\]                                                    ?.(i)                    Intercept on x-axis is \[2\sqrt{({{g}^{2}}-c)}=5\]                    \[\therefore \ 4({{g}^{2}}+4g+4)=25\] by (i)                    or \[(2g+9)(2g-1)=0\Rightarrow g=-\frac{9}{2},\ \frac{1}{2}\]                    Since centre \[(-g,\ -f)\] lies in 1st quadrant, we choose \[g=-\frac{9}{2}\] so that \[-g=\frac{9}{2}\] (positive).                    \[\therefore \ c=14\], (from (i)).


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